harshin nechooli
Last Activity: 6 Years ago
here the particles will mone in the same verification lines and there is no horizontal motion
then you can write the coordinates of both particle for a particular instant that gives it's coordinates then
simply evide it by 2 it will give you the coordinate of B
coordinate of A =vt. of C = (1÷2) a(t^2)
then diferrence in y coordinate = vt - half at^2
then coordinate of B =1÷2 (vt -. 1÷2 at^2)
or. (v÷2)t. +. (- a÷2)t^2 ÷2
that gives velocity and acceleration to be v÷2 and -a÷2