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At the initial moment three points A ,B and C are on a horizontal straight line at equal distances from one another. Point A begins to move vertically upward with constant velocity v and. C vertically downward without any initial velocity at constant acceleration a .Assuming the points begin to move simultaneously , then for all the points to be constantly on one straight line ,the point B moves with : 1. Acceleration a by 2 An initial velocity v/2 both upwards 2. Retardation a / 2 and initial velocity v / 2both upwards 3. Zero acceleration and initial velocity v 4. Acceleration a/ 2 and initial velocity v both downwards

At the initial moment three points A ,B and C are on a horizontal straight line at equal distances from one another.  Point A begins to move vertically upward with constant velocity v and. C vertically downward without any initial velocity at constant acceleration a .Assuming the points begin to move simultaneously , then for all the points to be constantly on one straight line ,the point B moves with :
1. Acceleration a by 2 An initial velocity v/2  both upwards
2. Retardation a / 2 and initial velocity v / 2both upwards
3. Zero acceleration and initial velocity v
4. Acceleration a/ 2 and initial velocity v both downwards

Grade:11

2 Answers

Khimraj
3007 Points
5 years ago
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hope it clears.................................................................
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harshin nechooli
121 Points
5 years ago
here the particles will mone in the same verification lines and there is no horizontal motion 
 then you can write the coordinates of both particle for a particular instant  that gives it's coordinates then 
simply evide it by 2   it will give you the coordinate of B  
coordinate of A =vt.      of C = (1÷2) a(t^2)
then diferrence in y coordinate  = vt - half at^2
then coordinate of B =1÷2 (vt -. 1÷2 at^2) 
or.         (v÷2)t. +. (- a÷2)t^2 ÷2
that gives velocity and acceleration to be     v÷2 and   -a÷2
 
 

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