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        Assuming complete dissociation of H2SO4 as: $\dpi{100} \fn_cm (H_2SO_4+2H_2O \rightarrow 2H_3O^+SO_4^{2-})$The number of H3O+ ions in 10 ml of 0.5 N H2SO4 is        a) 3.01 × 1021 b) 1.5 × 1021 c) 6.02 × 1021d) 3.01 × 1022
one year ago

## Answers : (3)

Vishnu
16 Points
							Imole=6.022*10^23In one mole of H3o 0.5moles are thereSo   6.022*10^23*0.5/2=3.01*10^21/2~1.5*10^23 😉 And, :A

one year ago
Vishnu
16 Points
							1 Mole =6.022*10^23NSo, in ½ or0.5 moles of H3O has 1/2*6.022*10^23*N are there so ans is 1.5*10^21Ans A

one year ago
aswanth nayak
100 Points
							Dear Student,  1 Mole =6.022*10^23NSo, in ½ or0.5 moles of H3O has 1/2*6.022*10^23*N are there so ans is 1.5*10^21Correct Answer is option A

11 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions