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Assume that the standard kilogram would weigh exactly 9.80 N at sea level on the equator if the Earth did not rotate. Then take into account the fact that the Earth does rotate, so that this object moves in a circle of radius 6370 km (the Earth's radius) in one day. (a) Determine the centripetal force needed to keep the standard kilogram moving in its circular path. (b) Find the force exerted by the standard kilogram on a spring balance from which it is suspended at the equator (its apparent weight).

Assume that the standard kilogram would weigh exactly 9.80 N at sea level on the equator if the Earth did not rotate. Then take into account the fact that the Earth does rotate, so that this object moves in a circle of radius 6370 km (the Earth's radius) in one day. (a) Determine the centripetal force needed to keep the standard kilogram moving in its circular path. (b) Find the force exerted by the
standard kilogram on a spring balance from which it is suspended at the equator (its apparent weight).

Grade:10

1 Answers

Jitender Pal
askIITians Faculty 365 Points
6 years ago

235-2243_1.PNG
Therefore the centripetal force on the object is 0.0336 N . 235-832_1.PNG
Therefore the force exerted by the standard kilogram on a spring balance from which it is suspended at the equator is 9.76 N .

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