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Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is P and L is its latent heat of vaporization. (a) pL/T (b) √T/pL (c) T/pL (d) 2T/pL

Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is P and L is its latent heat of vaporization.
(a) pL/T
(b) √T/pL
(c) T/pL
(d) 2T/pL

Grade:upto college level

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
7 years ago
(d). When radius is by ∆R,
4πR2∆RpL = 4πT[R2 – (R - ∆R]
\RightarrowpR2∆RL = T[R2 – R2 + 2R∆R - ∆R2]
\RightarrowpR2∆RL =T2R∆R [ ∆R is very small ]
\RightarrowR = 2T/pL

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