0

Guest

Courses New

Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is P and L is its latent heat of vaporization. (a) pL/T (b) √T/pL (c) T/pL (d) 2T/pL

Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is P and L is its latent heat of vaporization.
(a) pL/T
(b) √T/pL
(c) T/pL
(d) 2T/pL

Grade:upto college level

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
9 years ago
(d). When radius is by ∆R,
4πR2∆RpL = 4πT[R2 – (R - ∆R]
\RightarrowpR2∆RL = T[R2 – R2 + 2R∆R - ∆R2]
\RightarrowpR2∆RL =T2R∆R [ ∆R is very small ]
\RightarrowR = 2T/pL

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More