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`        Assume that a drop of liquid evaporates by decrease in its surface energy, so that its temperature remains unchanged. What should be the minimum radius of the drop for this to be possible? The surface tension is T, density of liquid is P and L is its latent heat of vaporization.(a) pL/T(b) vT/pL(c) T/pL(d) 2T/pL`
5 years ago

## Answers : (1)

Kevin Nash
332 Points
```

(d).
When radius is by ?R,

4pR2?RpL
= 4pT[R2 – (R - ?R]

? pR2?RL
= T[R2 – R2 + 2R?R - ?R2]

?
pR2?RL =T2R?R [ ?R is very
small ]

?
R = 2T/pL

```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions