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Aparticle is projected upwards with an initial velocity 40m/s .Find the distance and displacement covered by particle in6 seconds.

dhruv singh , 7 Years ago
Grade 10
anser 1 Answers
uday

Last Activity: 7 Years ago

v^2 – u^2 = 2as
 
consider v=0
               u=40
               a= -10
tundefinedore
               0-1600= -20*s
                 
                     
ie;         s=80
 
 
     this means that the projectile will come to rest only when 80m is covered
 
  now, using 
             s=ut + ½at^2
 
            s=240-180   (since a=g=-10)
            s=60 meter
 
     therefore both distance covered and displacement are equal
         
           ie:::ans::::      60m
  
 

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