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Answer is 4) 5m.Reference figure along with question is given in question.Please answer me as early as possible.
Now by energy conservationKi + Ui=kf + Uf0 + mg1=1/2mv*vFrom this v= sqrt(2g)When they collide and due to similar masses Collision is elastic and the velocity of 1 is taken by 2 now V2=sqrt(2g)But there is friction Now friction = 0.2*m*gSince friction is a backward force results in retardationThen accn = 0.2*m*g/m = 0.2g = 2m/ s*sHence block moves with v2 velocity under retardation and after sometime it stopsVfinal= 0By third eq of motion0=20 - 4 ss=5
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