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Grade: 11

                        

Answer is 4) 5m.Reference figure along with question is given in question.Please answer me as early as possible.

Answer is 4) 5m.Reference figure along with question is given in question.Please answer me as early as possible.

3 years ago

Answers : (1)

Swayam Singh
24 Points
							Now by energy conservationKi + Ui=kf + Uf0 + mg1=1/2mv*vFrom this v= sqrt(2g)When they collide and due to similar masses Collision is elastic and the velocity of 1 is taken by 2 now V2=sqrt(2g)But there is friction Now friction = 0.2*m*gSince friction is a backward force results in retardationThen accn = 0.2*m*g/m                   = 0.2g = 2m/ s*sHence block moves with v2 velocity under retardation and after sometime it stopsVfinal= 0By third eq of motion0=20 - 4 ss=5
						
3 years ago
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