×

#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```
Answer is 4) 5m.Reference figure along with question is given in question.Please answer me as early as possible.
Answer is 4) 5m.Reference figure along with question is given in question.Please answer me as early as possible.

```
3 years ago

Swayam Singh
24 Points
```							Now by energy conservationKi + Ui=kf + Uf0 + mg1=1/2mv*vFrom this v= sqrt(2g)When they collide and due to similar masses Collision is elastic and the velocity of 1 is taken by 2 now V2=sqrt(2g)But there is friction Now friction = 0.2*m*gSince friction is a backward force results in retardationThen accn = 0.2*m*g/m                   = 0.2g = 2m/ s*sHence block moves with v2 velocity under retardation and after sometime it stopsVfinal= 0By third eq of motion0=20 - 4 ss=5
```
3 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions