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An open U tube of uniform cross section contains mercury .If 27.2 cm of water column is poured into one climb , how high does the mercury surface rise in other climb from its initial volume.?
An open U tube of uniform cross section contains mercury .If 27.2 cm of water column is poured into one climb , how high does the mercury surface rise in other climb from its initial volume.?

```
3 years ago

## Answers : (3)

Abcd
12 Points
```							P○ + density of water × height of water ×g= P○ + density of mercury ×height of mercury [ raised height] ×g1×27.2=13.6 ×hh= 2cmThe level pf mercury rise by 2 cm from its initial volume
```
2 years ago
Abcd
12 Points
```							When the water is poured into one limb the mercury level in that limb decreases by h height and in creases in the other by hTherefore pressure of decreased hieght h and the same level in other limb is sme And hence the height for the second limb should be taken as 2hP○ + 27.2×1×g=13.6×2h×g27.2=13.6×2h2h=2h=1
```
2 years ago
ankit singh
609 Points
```							When the water is poured into one limb the mercury level in that limb decreases by h height and in creases in the other by hTherefore pressure of decreased hieght h and the same level in other limb is smeAnd hence the height for the second limb should be taken as 2hP○ + 27.2×1×g=13.6×2h×g27.2=13.6×2h2h=2h=1
```
6 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions