Grade 12th passMechanics

An object starts from rest with constant acceleration 4 m/s^2, then find the distance travelled by object in 5th half seconds.

Vikash Kumar Singh

8 Years agoGrade 12th pass

2 Answers

sonika p

8 Years ago

initial velocity, u=0, a=4m/s2

distance travelled in time t =1/2*a*(t^2)

distance travelled in 5^th half seconds = total distance travelled – distance travelled in 4^th half seconds

= 1/2[a*t*t]-1/2[a*t*t]

=1/2[4*(5/2)^2]-1/2[4*(4/2)^2]

=1/2[4*(25-16)/4]

=1/2*(9)=4.5m

thus, distance travelled in 5^th half seconds is 4.5m

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An object starts from rest with constant acceleration 4 m/s^2, then find the distance travelled by object in 5th half seconds.

Vikash Kumar Singh

2 Answers

sonika p

Harsh Sharma

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