Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        An object of mass 1kg moving on a horizontal surface with initial velocity 8m/s comes to rest after 10s . If one wants to keep the object moving on the same surface with velocity 8m/s the force required is....1. 0.4N2. 0.8N3. 1.2N4. Zero
2 years ago

Diwankar singh
14 Points
							mass=1kginitial velocityu=8m/sfinal velocityv=0m/stime=10 sec.therefore,                  acceleration=v-u/t                                      =0-8/10                                      =-0.8m/s^2Force=mass*acceleration          =1*(-0.8)          =   -0.8NWe know that force cannot be in negative    therefore, force applied =0.8N

2 years ago
nidhi
35 Points
							v = u + atv = 00 = 8 – $\displaystyle \mu$g(10)$\mu$ = 8/100 = 0.08To move the body withconstant velocity on this surface, internal force applied should be equal to friction forceF = $\mu$mg   = (0.08)(1)(10)   = 0.8N

2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions