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Grade: 11
        
an object of mass 10kg move at constant speed 10m/s. A constant force that acts on object gives it a speed of 2m/s in opposite directions.The force acting on the object is.......
 
one year ago

Answers : (1)

Vikas TU
6874 Points
							
After giving a speed of 2 m/s in opposite direction
the net velocity becomes =>
v = 10 -2 = 8m/s.
As the force is constant accln. is constant and hence from Netwon’s fisrt law of eq. we get,
8 = 10 + at
at = -2
a = -2/t m/s^2
Thus U must need to provide the time for which the constant force has acted on the object in order to calculate the force for that particular interval of time,
Therfore,
F = m*a = > 10*2/t N
one year ago
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