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`        an object of mass 10kg move at constant speed 10m/s. A constant force that acts on object gives it a speed of 2m/s in opposite directions.The force acting on the object is....... `
3 years ago

Vikas TU
9795 Points
```							After giving a speed of 2 m/s in opposite directionthe net velocity becomes =>v = 10 -2 = 8m/s.As the force is constant accln. is constant and hence from Netwon’s fisrt law of eq. we get,8 = 10 + atat = -2a = -2/t m/s^2Thus U must need to provide the time for which the constant force has acted on the object in order to calculate the force for that particular interval of time,Therfore,F = m*a = > 10*2/t N
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions