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Grade 11Mechanics

An object of mass 0.5 kg is whirled at the end of string 0.8 m long. If the string makes three revolutions in 1.2 sec, find the tension in the string.

Profile image of umang mitter
11 Years agoGrade 11
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2 Answers

Profile image of Nirmal Singh.
11 Years ago
when object will move whirkled it will move in circular move. to move in circular motion tension will provide the centripetal force.

So T = mv2/r

and v = 2pi r / t

where t is the time period in one revolution t = 1.2 / 3 = 0.4 sec

T = m *(2pi r / t)2/ r

T = 4pi2r m / t2

T = (4*3.14*3.14 *0.8*0.5 ) / (0.4*0.4)

T = 98.596 N

Regards,
Nirmal Singh
Askiitians Faculty
Profile image of Pawan Kumar
8 Years ago
An object of mass 0.5 kg whirled at the end of string o.8 m long. If the string makes revolution in 1.2 . Find tension in the string