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an object of maas m1 moving with speed V collide with anorther object of mass m2 at rest stick to it. find the impulse imparted to second object?

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4 years ago

Vikas TU
14146 Points
```							From the momentum Conservation,m1v + 0 = (m1+m2)v’v’ = m1v/(m1+m2) m/s. J = change in momentum ( for second object.)that is = > Pf – Pi=> (m2)v’ - m2*0 => m1*m2*v/(m1+m2) N-m.
```
4 years ago
Piyush Kumar Behera
435 Points
```							Let v1 be the combined velocity of both the bodies after collision.Momentum of the system before collision=m1vmomentum of the system after collision =(m1+m2)v1As the total momentum is conserved,so m1v=(m1+m2)v1v1=m1v/(m1+m2)Momentum of m2 before collision=0momentum of m2 after collision =m2v1=m1m2v/(m1+m2)impulse imparted=final momentum – initial momentum=m1m2v/(m1+m2)-0=m1m2v/(m1+m2)so the impulse imparted to the second object is m1m2v/(m1+m2)
```
4 years ago
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• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions