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Grade 11Mechanics

An object moving with the speed of 6.25m/s, is decelerated at a rate given by dv/dt=–2.5 √v ?where v is the instantaneous speed. The time taken by the object, to come to rest would be?

Profile image of Chang
8 Years agoGrade 11
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1 Answer

Profile image of Arun
ApprovedApproved Tutor Answer8 Years ago
Dear student
 
we have 
dv / dt =  – 2.5 \sqrtv
 
dt =  – dv / \small \sqrtv
 
on Integration
 
t =  [– 0.8 \small \sqrtv ] from 6.25 to 0
 
t = 2sec
 
Regards
Arun (askIITians forum expert)