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Grade: 11

                        

An object moving with the speed of 6.25m/s, is decelerated at a rate given by:dv–2.5vdt?where v is the instantaneous speed. The time taken by the object, to come to rest would be?

4 years ago

Answers : (2)

Vikas TU
12277 Points
							
dv = – 2.5 v dt
integerating both sides,
dv/v   = -2.5dt
logv = -2.5t
to come to rest velcity should be zero
and log0 = – infinity
therefore,
from the concept the object would never stops .
4 years ago
dhiraj Raj
11 Points
							
 Dv/√v=-2.5dt
integrating both side,
2√v=-2.5t+k
at t=0, v=6.25
2*2.5=k=5
therefore for v=0,
t=2 sec............
2 years ago
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