An object moving with speed 6.25m/s is decelarated at given by dv /dt =-2.5root where v is instaneous speed. The time taken to rest

Question

Arun · Answer

We have dv/dt = -2.5 v^1/2 dt = dv/ -2.5 v^1/2 So the total time taken is On integrating t = [-0.8 v^1/2] 0 6.25 t = 2 sec. So the object would take two seconds to come to rest.

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

We have
dv/dt = -2.5 v^1/2
dt = dv/ -2.5 v^1/2
So the total time taken is
On integrating
t = [-0.8 v^1/2]06.25
t = 2 sec.
So the object would take two seconds to come to rest.

Thanks and Regards

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An object moving with speed 6.25m/s is decelarated at given by dv /dt =-2.5root where v is instaneous speed. The time taken to rest

An object moving with speed 6.25m/s is decelarated at given by dv /dt =-2.5root where v is instaneous speed. The time taken to rest

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