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An object is projected with velocity v. If the range (R) of this object is double the maximum height H, then its range will be???

Aanshi , 7 Years ago
Grade 11
anser 1 Answers
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Last Activity: 7 Years ago

Data is insufficient. We can get range in terms of initial velocity though.
U2sin2theta/g=2U2sin2theta/2g
Tan theta=2, theta= tan-12
Looking up value of tan inverse 2, we get it as 63.4349
Range=U2sin2(63.4349)/g
Sin2(63.4349)=4/5
Answer is 2U2/25
 

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