An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?

Question

Arun · Answer

Dear student g = 9.8 m/sec = 35.28 km/hr From V&sup2; = u&sup2; - 2 * g* s 0 = (88.2)&sup2; - 2 * 35.28 * h h = 7779.24/70.56 h = 110.25 km Regards Arun (askIITians forum expert)

atulya yadav · Answer

First conver initial velocity 88.2 km per hr in meter per second then use formula for height that is (u×u×sin(angle of projectile with horizontal that is 90 degree bcoz it is give vertically×sin90/2g and get ur answer of a part that is max height for b part use formula 2usin90/g here u aslo in meter per second

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An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?

An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?

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An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?

An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?

2 Answers

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