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Grade: 12th pass
        
An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?
one year ago

Answers : (2)

Arun
18564 Points
							
Dear student
 
g = 9.8 m/sec = 35.28 km/hr
From 
V² = u² - 2 * g* s
0 = (88.2)² - 2 * 35.28 * h
h = 7779.24/70.56
h = 110.25 km
 
Regards
Arun (askIITians forum expert)
one year ago
atulya yadav
27 Points
							First conver initial velocity 88.2 km per hr in meter per second then use formula for height that is (u×u×sin(angle of projectile with horizontal that is 90 degree bcoz it is give vertically×sin90/2g  and get ur answer of a part that is max height for b part use formula 2usin90/g  here u aslo in meter per second
						
one year ago
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