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`        An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?`
one year ago

Arun
23389 Points
```							Dear student

g = 9.8 m/sec = 35.28 km/hr
From
V² = u² - 2 * g* s
0 = (88.2)² - 2 * 35.28 * h
h = 110.25 km

Regards
```
one year ago
27 Points
```							First conver initial velocity 88.2 km per hr in meter per second then use formula for height that is (u×u×sin(angle of projectile with horizontal that is 90 degree bcoz it is give vertically×sin90/2g  and get ur answer of a part that is max height for b part use formula 2usin90/g  here u aslo in meter per second
```
one year ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions