An object is projected vertically upward with a speed of 88.2 km/h. a) how high does the projectile go? b) how long does it take projectile to return to its point projection?
maria , 7 Years ago
Grade 12th pass
2 Answers
Arun
Last Activity: 7 Years ago
Dear student
g = 9.8 m/sec = 35.28 km/hr
From
V² = u² - 2 * g* s
0 = (88.2)² - 2 * 35.28 * h
h = 7779.24/70.56
h = 110.25 km
Regards
Arun (askIITians forum expert)
atulya yadav
Last Activity: 7 Years ago
First conver initial velocity 88.2 km per hr in meter per second then use formula for height that is (u×u×sin(angle of projectile with horizontal that is 90 degree bcoz it is give vertically×sin90/2g and get ur answer of a part that is max height for b part use formula 2usin90/g here u aslo in meter per second
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