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An object is kept at x = 0, a force on the object is F (constant) from t =0. Friction coefficient vary as μ=cx. Then the distance travelled by the block is

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4 years ago

Vikas TU
14146 Points
```							Distance travelled by the block =>Net Force on block = > F – uMg = Maa =  acceleration of block.F = M[cgx + vdv/dx]vdv = Fdx/M  –  cgxdxintegerating both sides,v^2/2 = Fx/M -cgx^2/2v = root(2xF/M – cgx^2) v would be zero at last.hence, 2F/M – cgx = 0or x = 2F/cgM is the distance covered by the block.
```
4 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions