Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
An object is kept at x = 0, a force on the object is F (constant) from t =0. Friction coefficient vary as μ=cx. Then the distance travelled by the block is
Distance travelled by the block =>Net Force on block = > F – uMg = Maa = acceleration of block.F = M[cgx + vdv/dx]vdv = Fdx/M – cgxdxintegerating both sides,v^2/2 = Fx/M -cgx^2/2v = root(2xF/M – cgx^2) v would be zero at last.hence, 2F/M – cgx = 0or x = 2F/cgM is the distance covered by the block.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -