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Grade: 11
         An object having a velocity 4.0 m/s is accelerated at the rate of 1.2 m/s2 for 5.0 s. Find the distance travelled during the period of acceleration.
5 years ago

Answers : (2)

Aditi Chauhan
askIITians Faculty
396 Points
							Sol. u = 4 m/s, a = 1.2 m/s2, t = 5 sec
Distance = s =  ut = + ½ at2
= 4(5) + 1/2 (1.2)52 = 35 m.

						
5 years ago
Rizwan
13 Points
							
Sol. Given u=4m/s , a = 1.2 m/sand time = 5 secs. 
Distance = s = ut + 1/at2 = 4(5)+1/(1.2)(5)2
                            =20 + 1/2  (1.2) (25) 
                       = 20 + 3 (5) 
                        = 35 m 
                                Ans.
one year ago
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