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An object has velocityrelative to the ground. An observer moving past with a constant velocityrelative to the ground measures the velocity of the object to be(relative to the observer). The magnitudes of these velocities are related by(A) v0 ≤ v1 + v2.(B) v1 ≤ v2 + v0.(C) v2 ≤ v0 + v1.(D) All the above are true.

Simran Bhatia , 9 Years ago
Grade 11
anser 1 Answers
Aditi Chauhan

Last Activity: 9 Years ago

The correct option is: (C) v2 < v0 + v1.
The object moving with velocity \overrightarrow{v_{o}}relative to ground observe the maximum velocity of object moving with velocity\overrightarrow{v_{1}} , when both objet move in the opposite direction relative to each other such that
v2 = v0 + v1
For any other direction of motion between object moving with velocity \overrightarrow{v_{0}}and object moving with velocity \overrightarrow{v_{1}}, the relative speed as observed by the object moving with velocity \overrightarrow{v_{1}}will be less than v0 + v1 .
Therefore, the magnitude of velocity of object moving with velocity \overrightarrow{v_{0}}relative to the object moving with velocity\overrightarrow{v_{1}} will always be less than or equal to the sum of their velocity with respect to ground, that is
v2 \leq v0 + v1
Therefore, (C) is the correct option and the rest are ruled out.



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