An isolated unit north pole experience a force of 2×10000000 when kept at a distance of 1m from a magnetic pole in air the pole strength of the pole is

We will use Coulomb’s Law for Magnetism to solve this problem. The formula for the force between two magnetic poles is:

F = (μ₀ * m₁ * m₂) / (4π * r²)

Where:

F = Force between the poles (N)
μ₀ = Permeability of free space = 4π × 10⁻⁷ T·m/A
m₁ = Pole strength of the first pole (A·m)
m₂ = Pole strength of the second pole (A·m)
r = Distance between the poles (m)
Given:
F = 2 × 10⁷ N
r = 1 m
The first pole is an isolated unit north pole (m₁ = 1 A·m)
Medium is air, so μ₀ = 4π × 10⁻⁷ T·m/A
Step-by-step Calculation:
Rearrange the formula to solve for m₂:

m₂ = (F * 4π * r²) / (μ₀ * m₁)

Substituting the values:

m₂ = (2 × 10⁷ * 4π * (1)²) / (4π × 10⁻⁷ * 1)

Cancel 4π from numerator and denominator:

m₂ = (2 × 10⁷) / (10⁻⁷)

m₂ = 2 × 10¹⁴ A·m

Final Answer:
The pole strength of the magnetic pole is 2 × 10¹⁴ A·m.