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Grade: 12th pass
        An ideal massless spring S can be concourse 1m by a force of 100N in equip equilibrium. The same spring is placed at the bottom of a frictionless inclined plane inclined Addy 30° to the horizontal. A 10 kg block M is released  from the rip of incline and is brought to rest momentarily after compressng the spring by 2m.if g=10 m/s2.what is the speed of mass just before it touches the spring
one year ago

Answers : (1)

Umakant biswal
5349 Points
							
It is given that force of 100N is applied for compression of 1m.
F=kx
100=k(1) So, k=100N/m
Now, the whole kinetic energy of the block is converted into spring potential energy.
So,
1/2mv^2=1/2kx^2
Cancelling 1/2 from both the sides.
mv^2=kx^2
then 
10*v^2=100(2)^2 . 
Becuase it is given that it compresses the spring by 2m
so,

v^2=100*4/10
v^2=40
so, v = root 40 
which is the answer 
HOPE IT CLEARS 
​ALL THE BEST 

 
one year ago
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