An empty 20000 kg coal wagon is moving on a level track at 5m/s. Suddenly 5000kg of coal is dumped into it directly from above. The coal initially has zero horizontal velocity. The final speed of the wagon is

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Arun · Answer

According to conservation of momentum- M1 * v1 = M2* v2 20000* 5 = 25000 * v2 100000/25000 = v2 V2 = 4 m/sec

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An empty 20000 kg coal wagon is moving on a level track at 5m/s. Suddenly 5000kg of coal is dumped into it directly from above. The coal initially has zero horizontal velocity. The final speed of the wagon is

An empty 20000 kg coal wagon is moving on a level track at 5m/s. Suddenly 5000kg of coal is dumped into it directly from above. The coal initially has zero horizontal velocity. The final speed of the wagon is

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An empty 20000 kg coal wagon is moving on a level track at 5m/s. Suddenly 5000kg of coal is dumped into it directly from above. The coal initially has zero horizontal velocity. The final speed of the wagon is

An empty 20000 kg coal wagon is moving on a level track at 5m/s. Suddenly 5000kg of coal is dumped into it directly from above. The coal initially has zero horizontal velocity. The final speed of the wagon is

1 Answers

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