An elevator in which a man is standing is moving upwards with a speed of 10m/s. If the man drops a coin from a height of 2.45m from the floor of the elevator, it reaches the floor of the elevator after a time-(g=9.8m/s2).21/2sec 1/21/2sec. 2sec. 1/2 sec. Answer is B.Can you show me the simplification for this question?
kushi , 9 Years ago
Grade 12
1 Answers
bhavana
Last Activity: 7 Years ago
with respect to an observer on ground the coin when relased will freely fall i.e. the initial vel of the coin is 0 using s=1/2gt^2 2.45*2=gt^2 t^2=4.9/9.8=2 t=(1/2)^2
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