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question mark

an elevator car whose floor to ceiling distance is equal to 2.7 m starts ascending with a constant acceleration of 1.2 m/s square two sec after a bolt begins to fall from the ceiling of the elevator find
the bolt’s free fall time and the displacement and distance covered by the bolt during the fall from the ceiling with respect to ground

trishna , 11 Years ago
Grade 12
anser 1 Answers
Abhishek Kumar
Bolt falls from initial velocity = velocity of car after 2 second = 1.2X2 = 2.4 sec
time taken in coming to ground,
u = 2.4 m/s
a= -g + 1.2 (In car’s frame)
s= 2.7 m
find t

For distance, first find time when velocity becomes zero and the distance travelled then. Finally distance travelled with velocity along direction of g.
Last Activity: 11 Years ago
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