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an elevator car whose floor to ceiling distance is equal to 2.7 m starts ascending with a constant acceleration of 1.2 m/s square two sec after a bolt begins to fall from the ceiling of the elevator find the bolt’s free fall time and the displacement and distance covered by the bolt during the fall from the ceiling with respect to ground

 
an elevator car  whose floor to ceiling distance is equal to 2.7 m starts ascending with a constant acceleration of 1.2 m/s square two sec after a bolt begins to fall from the ceiling of the elevator find
the bolt’s free fall time and the displacement and distance covered by the bolt during the fall from the ceiling with respect to ground

Grade:12

1 Answers

Abhishek Kumar
askIITians Faculty 253 Points
6 years ago
Bolt falls from initial velocity = velocity of car after 2 second = 1.2X2 = 2.4 sec
time taken in coming to ground,
u = 2.4 m/s
a= -g + 1.2 (In car’s frame)
s= 2.7 m
find t

For distance, first find time when velocity becomes zero and the distance travelled then. Finally distance travelled with velocity along direction of g.

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