An electric of 2 HP has an efficiency of 60%. If it works to lif water from a well of depth 20m for 10 min, find how much water will be left on the ground. (Take g=10m/s) *Please explain what an HP is and how to solve this problem. *

Question

Vikas TU · Answer

HP stands for Horse Power and 1 HP =746 watts. since the efficiency is 60% Power used to lift up the water => 0.6 * 2*746 = > 895.2 Watt. P =W/t P = mgh/t 895.2 = m(10)(10)/(10*60) m = 5371.2 g or 5.3712 kg of water.

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An electric of 2 HP has an efficiency of 60%. If it works to lif water from a well of depth 20m for 10 min, find how much water will be left on the ground. (Take g=10m/s) Please explain what an HP is and how to solve this problem.

An electric of 2 HP has an efficiency of 60%. If it works to lif water from a well of depth 20m for 10 min, find how much water will be left on the ground. (Take g=10m/s)

Please explain what an HP is and how to solve this problem.

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An electric of 2 HP has an efficiency of 60%. If it works to lif water from a well of depth 20m for 10 min, find how much water will be left on the ground. (Take g=10m/s) *Please explain what an HP is and how to solve this problem. *

An electric of 2 HP has an efficiency of 60%. If it works to lif water from a well of depth 20m for 10 min, find how much water will be left on the ground. (Take g=10m/s) *Please explain what an HP is and how to solve this problem. *

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An electric of 2 HP has an efficiency of 60%. If it works to lif water from a well of depth 20m for 10 min, find how much water will be left on the ground. (Take g=10m/s) Please explain what an HP is and how to solve this problem.

An electric of 2 HP has an efficiency of 60%. If it works to lif water from a well of depth 20m for 10 min, find how much water will be left on the ground. (Take g=10m/s)

Please explain what an HP is and how to solve this problem.