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Grade 11Mechanics

An elastic ball P strikes a moving elevator with a velocity V perpendicular to elevator surface. If the
elevator has a constant upward velocity V, then the maximum height attained by the ball after the first
collision and before the second collision measured from the position of first collision is : (g is vertically
downwards)

Profile image of Anonymous
8 Years agoGrade 11
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1 Answer

Profile image of Aditya Rana
8 Years ago
Let us assume that the velocity of elevator is 0. So the velocity with which the ball strikes the elevator would be velocity of ball plus velocity of elevator which is 2v. Elastic collision would give an equal velocity in upward direction. Now apply third kinematic equation by putting the value of v as 0 and u as 2v to get the answer as 2v^2/g