Arun
Last Activity: 6 Years ago
Hello Dear.
Given Conditions ⇒
Initial linear velocity(u) = 54 km/hr.
= 54 × 5/18 [Changing into m/s.]
= 15 m/s.
Radius of the wheel(r) = 0.35 m.
Now, Using the Formula,
Initial Angular Velocity (ω₁) = u/r
ω₁ = 15/0.35
ω₁ = 42.86 radian/sec.
Also, Final Angular Velocity (ω₂) = 0
Now, Using the Formula,
Angular Acceleration (α) = (ω₂ - ω₁)/t
= (0 - 42.86)/15
= - 2.86 radian/sec²
Moment of Inertia about the axis of the rotation(I) = 3 kg-m²
∴ Torque = I × α
⇒ Torque = 3 × -2.86
⇒ Torque = -8.58 Nm.
Hence, the average negative torque is -8.58 N-m.
Regards
Arun (askIITiams forum expert)
