Grade 11Mechanics
An athelete takes 2.0 s to reach his maximum speed of 18.0 km/h. What is the magnitude of his average acceleration?
3 Answers
Kevin Nash
Sol. Initial velocity u = 0 (∴ starts from rest)
Final velocity v = 18 km/hr = 5 sec
(i.e. max velocity)
Time interval t = 2 sec.
∴ Acceleration = aave = (v-u )/t = 5/2 = 2.5 m/s2.
Dhiraj
This question is very simple.
You just need to find average acceleration.
Formula:v-u/t
U=0
V=18×5/18=5 m/s
T=2s
a=5/2 =2.5 m/s2
Vikas TU
Initial velocity=u= 0 m/s
Final velocity =v=18km/hr=18x5/18=5 m/s
time= 2sec
Average acceleration =a=?
Final velocity =v=18km/hr=18x5/18=5 m/s
time= 2sec
Average acceleration =a=?
Formula to be used : a= v-u/t
a=5-0/2 =2.5 m/s²
∴ Magnitude of his average acceleration is 2.5m/s²
∴ Magnitude of his average acceleration is 2.5m/s²
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