An aircraft flies at 400 km/h in still air . A wind of 200√2 km/h is blowing from the south . The pilot wishes to travel from A to a point B north east of A . Find the direction he must steer and the time of his journey if AB = 1000 km.

Question

Vikas TU · Answer

we know the resulatnt. that is north east of A. Therefore, let v km / h be the change in velocity of aircraft. then, perpendiclar / hypertenuse = sin45. 200root2/root((400+v)^2 + (200root2)^2) = sin45. Solve here for v.

Gkmeruva · Answer

Vp/sin 45°=Vw/sin x 400/1/√2=200√2/sin x Sin x*400=200√2*1/√2 Sin x=1/2 x=30° Time =distance/velocity= Vpg=√Vp^2+Vw^2+2*Vp*Vw*cos(45+x) Vpg=√400^2+200√2^2+2*400*200√2cos75° Vpg=√200(800)+400+800√2*0.2588 =546.399m/s T=d/V=1000/546-399 T=1.83hr

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An aircraft flies at 400 km/h in still air . A wind of 200√2 km/h is blowing from the south . The pilot wishes to travel from A to a point B north east of A . Find the direction he must steer and the time of his journey if AB = 1000 km.

An aircraft flies at 400 km/h in still air . A wind of 200√2 km/h is blowing from the south . The pilot wishes to travel from A to a point B north east of A . Find the direction he must steer and the time of his journey if AB = 1000 km.

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