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Grade: 12
        
an aeroplane has togo from A to B ,500 km away due to 30degrees east of north. a wind is blowing due to north at a speed of 20 .the air speed of plane is 150.find direction and time taken to go from A to B
 
3 months ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
3756 Points
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3 months ago
Vikas TU
10364 Points
							
Dear student 
Resultant speed of aeroplane=R at an angle 30 degree from North
Speed of wind = 20 m/s at an angle 0 degree from North
Speed of aeroplane in the air 150 m/s direction at an angle theta degree from North
Using sin law in triangle formed
20/sin(theta-30) =150/sin30
sin(theta-30)/20=sin30/150
Sin ( theta-30)=(1/300)*20=1/15=0.0667=sin 3.8
Theta = 33.8 degree
Hope this helps 
Good Luck 
3 months ago
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