Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        an aeroplane has togo from A to B ,500 km away due to 30degrees east of north. a wind is blowing due to north at a speed of 20 .the air speed of plane is 150.find direction and time taken to go from A to B `
3 months ago

## Answers : (2)

Saurabh Koranglekar
3756 Points
```
```
3 months ago
Vikas TU
10364 Points
```							Dear student Resultant speed of aeroplane=R at an angle 30 degree from NorthSpeed of wind = 20 m/s at an angle 0 degree from NorthSpeed of aeroplane in the air 150 m/s direction at an angle theta degree from NorthUsing sin law in triangle formed20/sin(theta-30) =150/sin30sin(theta-30)/20=sin30/150Sin ( theta-30)=(1/300)*20=1/15=0.0667=sin 3.8Theta = 33.8 degreeHope this helps Good Luck
```
3 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions