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`        an aeroplane fly along a straight path AB and return back again. The distance between A and B is l, and the aeroplane maintain the constant speed v w.r.t wind.There is a steady wind with  speed u and at angle ‘theta” with the line AB. Then calculate total time if the trip.`
4 months ago

Vikas TU
9449 Points
```							Hiii Just check ,i have answered the same question earlier , you just need to find the horizonta component of wind, which will be in relative velocity to the aeroplane traveled , and , take the relative velocity in coming nd going , and find the time accordingly and at last add both of them.Regard
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4 months ago
Khimraj
3008 Points
```							Does “AB=1” mean “the distance from A to B is 1?”If so, the time (distance divided by speed) in the downwind half is1/ V +vAnd the time in the upwind half is1/ V-vSo, the total time is (1/V+v) + (1/V-v)Working toward a common denominator,{(V-v) + (V+v)} / (V-v) (V+v)Then,2 V / V^2 + V v - V v -v^2Combining like terms,2 V / V^2 -v^2If V = 1, and v = .1, when AB = 1,2 / 1 - .012 / .99Total time is 2.02 unitsTo put this into a real-world scenario:Instead of AB being 1,AB= 100 milesV=100 mphv=10 mphDownwind time: 100/110Upwind time: 100/90Total time: (100/110) + (100/90)(9000/9900) + (11000/9900)20,000/9900Total time is 2.02 hoursThis is not the 2.00 hours found by doubling the distance and assuming the winds cancel out.
```
4 months ago
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Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions