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An 8000-N car is traveling at 12 m/s along a horizontal road when the brakes are applied. The car skids to a stop in 4.0 s. How much kinetic energy does the car lose in this time?
Dear student W = mg K = mv^2 /2 = Wv^2 /2g K = 8000 *12^2 /(2*9.8)= 59 Kj Hope this will help Good Luck
final kinetic energy is 0initial kinetic energy is 1/2mv2initial kinetic energy is 59 kilojoulehope this help
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