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Acceleration of the particle moving along x-axis varies with its x coordinate as a = 6x(x – 2)î The minimum velocity with which it can be projected from origin towards +x direction so that it does not come back to origin is ?

Samarjeet , 9 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 9 Years ago

find v first by integearting the accln. 6x(x – 2)
dv = (6x^2)dx  – 12xdx
v = 2x^3 – 6x^2
For minium vel.  a = 0
x = 0  and x = 2
put x = 2 in v and get the v.
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