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Abody is moving with a speed of 1 m/s and a force F is needed to stop it in a distance x. If the speed of body 3 m/ s , the force needed to stop it with the same distance x will be:
V² = u² + 2axa = v² - u² /2xa = 0 - 3²/2x= -9/2xIf initial vel is 1 m/sec, then force required is proportional to 1/2xWhen vel is 3m/sec, then force required is 9 times of the former.Hence force required = 9F
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