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Grade: upto college level

                        

A yo-yo (see Sample Problem 9-13) has a rotational inertia of 950 g . cm 2 and a mass of 120 g. Its axle radius is 3.20 mm and its string is 134 cm long. The yo-yo rolls from rest down to the end of the string. (a) What is its acceleration? (b) How long does it take to reach the end of the string? (c) If the yo-yo "sleeps" at the bottom of the string in pure rotary motion, what is its angular speed, in rev/s? (d) Repeat (c), but this time assume that the yo-yo was thrown down with an initial speed of 1.30 m/s

5 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
471 Points
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he solution for negative time has been neglected in solving the quadratic equation, and the therefore the time taken by the yo-yo to reach the bottom with initial speed of 1.30 m/s is 0.945 s.
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5 years ago
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Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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