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Grade: 11

                        

A worker drags a crate across a factory floor by pulling on a rope tied to the crate. The rope, which is inclined at 38.0° above the horizontal, exerts a force of 450 N on the crate. The floor exerts a horizontal resistive force of 125 N, as shown in Fig. Calculate the acceleration of the crate (a) if its mass is 96.0 kg, and (b) if its weight is 96.0 N.

5 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
							236-1595_1.PNG
Therefore, the horizontal acceleration of the crate of mass 96.0 kg is 2.40 m/s2.
Substitute 450 N for F in expression F 38.0°,
236-2189_1.PNG
The weight of the crate is larger than the upward force F sin (38.0°) , therefore the crate will rest on the ground.

236-1156_1.PNG
Therefore, the horizontal acceleration of the crate of weight 96.0 N is 23.4 m/s2.

236-2479_1.PNG
Therefore, the crate has an upward acceleration of 18.4 m/s2
5 years ago
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