0

Guest

Courses New

A worker drags a crate across a factory floor by pulling on a rope tied to the crate. The rope, which is inclined at 38.0° above the horizontal, exerts a force of 450 N on the crate. The floor exerts a horizontal resistive force of 125 N, as shown in Fig. Calculate the acceleration of the crate (a) if its mass is 96.0 kg, and (b) if its weight is 96.0 N.

A worker drags a crate across a factory floor by pulling on a rope tied to the crate. The rope, which is inclined at 38.0° above the horizontal, exerts a force of 450 N on the crate. The floor exerts a horizontal resistive force of 125 N, as shown in Fig. Calculate the acceleration of the crate (a) if its mass is 96.0 kg, and (b) if its weight is 96.0 N.

Grade:11

1 Answers

Aditi Chauhan
askIITians Faculty 396 Points
7 years ago
236-1595_1.PNG
Therefore, the horizontal acceleration of the crate of mass 96.0 kg is 2.40 m/s2.
Substitute 450 N for F in expression F 38.0°,
236-2189_1.PNG
The weight of the crate is larger than the upward force F sin (38.0°) , therefore the crate will rest on the ground.

236-1156_1.PNG
Therefore, the horizontal acceleration of the crate of weight 96.0 N is 23.4 m/s2.

236-2479_1.PNG
Therefore, the crate has an upward acceleration of 18.4 m/s2

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More