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A worker can lift a 75-kg block directly off the ground on to a loading dock, or can push the block up a friction less incline from the ground to the loading dock. Lifting the block requires 680 J of work to be done. Pushing the block up the incline requires a minimum applied force of 320 N. Find the angle the incline makes with the horizontal.
The incline has a height h where h = W=mg = (680 J)=[(75 kg)(9:81m=s2)]. The workrequired to lift the block is the same regardless of the path, so the length of the incline l is l =W=F = (680 J)=(320 N): The angle of the incline is then = arcsin hl= arcsin Fmg= arcsin(320 N)(75 kg)(9:81m=s2)= 25:8:
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