badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: upto college level

                        

A worker can lift a 75-kg block directly off the ground on to a loading dock, or can push the block up a friction less incline from the ground to the loading dock. Lifting the block requires 680 J of work to be done. Pushing the block up the incline requires a minimum applied force of 320 N. Find the angle the incline makes with the horizontal.

5 years ago

Answers : (2)

Navjyot Kalra
askIITians Faculty
654 Points
							232-237_1.JPG
						
5 years ago
abcde
21 Points
							The incline has a height h where h = W=mg = (680 J)=[(75 kg)(9:81m=s2)]. The workrequired to lift the block is the same regardless of the path, so the length of the incline l is l =W=F = (680 J)=(320 N): The angle of the incline is then = arcsin hl= arcsin Fmg= arcsin(320 N)(75 kg)(9:81m=s2)= 25:8:
						
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details