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# A wooden block of volume 1000 cm3 is suspended from a spring balance. It's weight is 12N in air. It is suspended in water such that half of the block is below the surface water. The reading of spring balance is

2 years ago

Arun
25333 Points

Volume of the wooden block=1000cm3ย =0.001 m3

Weight=Mg=12N

When half the ball is in water (density of water is 1 kg/m3), it experiences an upthrust due to half weight submerged apart from the weight force.ย

Immersed volume=500cm3ย =0.0005 m3

Upthrust=mass of the water displaced X g= (density of water) X (volume) X (g)

ย =(1) X (0.0005) X (10)=0.005 N

Net force on the block now is: downward weight - upthrust=12-0.005=11.995N

2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions