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Grade: 11

                        

A wooden block of volume 1000 cm3 is suspended from a spring balance. It's weight is 12N in air. It is suspended in water such that half of the block is below the surface water. The reading of spring balance is

2 years ago

Answers : (1)

Arun
25333 Points
							

Volume of the wooden block=1000cm3 =0.001 m3

Weight=Mg=12N

When half the ball is in water (density of water is 1 kg/m3), it experiences an upthrust due to half weight submerged apart from the weight force. 

Immersed volume=500cm3 =0.0005 m3

Upthrust=mass of the water displaced X g= (density of water) X (volume) X (g)

 =(1) X (0.0005) X (10)=0.005 N

Net force on the block now is: downward weight - upthrust=12-0.005=11.995N

2 years ago
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