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`        A wire has a mass (0.3+-0.003)g.,radius (0.5+-0.005)mm and length (6+-0.06)cm. The maximum percentage error in the measurement of its density is`
one year ago

Saurabh Koranglekar
8387 Points
```							Dear studentDensity = mass/ pi r*r*l%error = 1 + 2+ 1= 4%Regards
```
one year ago
Khimraj
3007 Points
```							your answer is "4%"___________Explainatioan =>______Since density is mass÷volume,For a cylinder it becomes- mass÷(pi×radius^2×length)Relative percent errors for-Mass-0.003÷0.3×100=1%Radius^2-2×0.005÷0.5×100=2%Length-0.06÷0.6×100=1%THE UNITS CANCEL THEMSELVES FROM THE NUMERATOR AND DENOMINATOR.therefore,maximum percentage error in density-1%+2%+1%=4%so, the answer is 4%
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions