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A wire fixed at the upper end stretches by length ℓ by applying a force F. The work done in stretching is
(a) 2F ℓ
(b) f ℓ
(c) F/2 ℓ
(d) F ℓ/2

Amit Saxena

12 Years agoGrade upto college level

3 Answers

Navjyot Kalra

12 Years ago

(d). Work done by constant force in displacing the object by a distatance ℓ
= 1/2 * stress * strain * volume
= 1/2 / F/A * ℓ/L * A * L = Fℓ/2

Mihir

8 Years ago

Work done is equal to 1/2 × stress × strain × volume U=1/2 × F/A × ∆l/l × AL = 1/2 × f ∆l ATQ = 1/2FL

Kushagra Madhukar

5 Years ago

Dear student,

Please find the answer to your question.

Work done by constant force in displacing the object by a distatance ℓ

= 1/2 * stress * strain * volume

= 1/2 / F/A * ℓ/L * A * L = Fℓ/2

Thanks and regards,

Kushagra

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View all Questions

A wire fixed at the upper end stretches by length ℓ by applying a force F. The work done in stretching is(a) 2F ℓ(b) f ℓ(c) F/2 ℓ(d) F ℓ/2

Amit Saxena

3 Answers

Navjyot Kalra

Mihir

Kushagra Madhukar

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A wire fixed at the upper end stretches by length ℓ by applying a force F. The work done in stretching is
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