Mechanics> (a) What is the centripetal acceleration ...

(a) What is the centripetal acceleration of an object on the Earth's equator due to the rotation of the Earth? (b) A 25.0-kg object hangs from a spring scale at the equator. If the free-fall acceleration due only to the Earth's gravity is 9.80 m/s², what is the reading on the spring scale?

Shane Macguire , 10 Years ago

Grade upto college level

1 Answers

Deepak Patra

Therefore, the acceleration of the point at equator of Earth is 0.033 m/s²

Round off to two significant figures,
T = 246 N
Therefore, the reading in spring scale is 246 N.

Last Activity: 10 Years ago

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Mechanics> (a) What is the centripetal acceleration ...

(a) What is the centripetal acceleration of an object on the Earth's equator due to the rotation of the Earth? (b) A 25.0-kg object hangs from a spring scale at the equator. If the free-fall acceleration due only to the Earth's gravity is 9.80 m/s2, what is the reading on the spring scale?

Shane Macguire , 10 Years ago

Deepak Patra

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