Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A wedge of mass m 1 and with angle rests on a horizontal surface. A block of mass m 2 is placed on the wedge. Assuming the friction to be negliible, find the acceleration of the wedge. Also find the acceleration of the block relative to the wedge.
FBD of block,We would get,N = m2gcos(alpha) {normal to wedge}andF = mgsin(alpha) {along the wedge}Hence along the wedge, accln. would be for the block. Hence,a2 = gsinalpha and the wedge would move rightwards only due to the Normal reaction from block in x direction component only.Hence,Nsin(alpha) = m1a1put N value we get,m2gcos(alpha)sin(alpha) = m1a1Relative accln. block w.r.t wedge would be =>a2 – a1 = gsin(alpha)*(1 – cos(alpha)) m/s^2
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -