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        A vessel at rest explodes, breaking into three pieces. Two pieces, having equal mass, fly off perpendicular to one another with the same speed of 30 m/s. The third piece has three times the mass of each other piece. What is the direction and magnitude of its velocity immediately after the explosion?
one year ago

Khimraj
3008 Points
							As external force is zero.apply conservation of momentum.m*0 = (m/5)*30$\hat{i}$ + (m/5)*30$\hat{j}$ + (3m/5)*vso v = -10$\hat{i}$ -10$\hat{j}$magnitude = 10$\sqrt{2}$Hole it clears............................................

one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions