A vessel at rest explodes, breaking into three pieces. Two pieces, one with twice the mass of the other, fly off perpendicular to one another with the same speed of 31.4 m/s. The third piece has three times the mass of the lightest piece. Find the magnitude and direction of its velocity immediately after the explosion. (Specify the direction by giving the angle from the line of travel of the least massive piece.)

Question

Shubham Singh · Answer

it makes angle tan -1 (2) with direction opposite to motion of lighter particle velocity is 31.4(root5)/3

Deepak Patra · Answer

The momentum of the third piece of vessel is given as:

Therefore the magnitude of velocity of third piece of vessel is 23.4 m/s.

Therefore the velocity vector of the third piece is at an angle 63.3° with respect to horizontal.

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