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Max. Height reached by each ball (h) = 5 m.
Final velocity, v =0
Let Initial velocity=u m/s
=> v^2 = u^2 - 2gh
=> 0=u^2 - 2×10×5
=> u^2 = 100
=> u = 10 m/s
Now, put u=10 in first equation of motion to get the value of time,
V = u - gt
=>0 = 10 -10t
=> t= 1 sec.
Time taken by each ball to reach the max. height = 1 sec.
Conversely,
No. of balls thrown in 1 sec. = 1
No. of balls thrown in 1 min. or 60 sec. =60 balls.
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