a uniformly acceletated body travels during the first two intervals of 6s distances of 30m and 80m.Find the distance travelled by the body at 20th second
Rup Banik , 5 Years ago
Grade 11
1 Answers
Arun
Last Activity: 5 Years ago
Dear student
s = ut + ½ at^2
30 = 6u + 18a
Also
110 = 12u + 72 a
on solving
36 a = 50
a = 50/36 = 25/18
also u= 5/6
hence distance travelled i. 20th second = u + ½ a (2 t – 1)
= 5/6 + ½ * 18/25 ( 39)
= 0.833 + (14.04)
= 14.873
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