A uniform wire having mass per unit length λ is placed over a liquid surface. The wire causes the liquid to depress by y (y

Question

Kevin Nash · Answer

Hello Student,

Please find the answer to your question

The free body diagram of wire is given below. If ℓ is the length of wire, then for equilibrium 2E sin θ = W.

F = S x ℓ

or, 2S x ℓ x sin θ = λ x ℓ x g

or, S = λg / 2sin θ

∴ S = λg / 2y / a = a λ g / 2 y [∵ sin θ = y /a]

Thanks
Kevin Nash
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A uniform wire having mass per unit length λ is placed over a liquid surface. The wire causes the liquid to depress by y (y

A uniform wire having mass per unit length λ is placed over a liquid surface. The wire causes the liquid to depress by y (y

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A uniform wire having mass per unit length λ is placed over a liquid surface. The wire causes the liquid to depress by y (y

A uniform wire having mass per unit length λ is placed over a liquid surface. The wire causes the liquid to depress by y (y

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