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Grade 12th passMechanics

A uniform thin rod of mass m length l is hanged with the help of of two identical springs of spring const. k
just after one is spring cut the acc. of the other spring is?
[HERE ROD IS SUSPENDED HORIZONTALLY AND TWO SPRINGS ARE ATTACH AT THE END POINTS OF ROD].

Profile image of manish majumdar
8 Years agoGrade 12th pass
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1 Answer

Profile image of ASHISH MEENA
8 Years ago
Initially 2kx =mgCase 1.Now if both springs are close to mid point Then final force due to remaining spring =kx=mg/2=> mg - mg/2 = ma => a =g/2If both springs are at end point..And released Acceleration will be the same.. but we have to right equation for torque about centre of mass of rodKx(l/2)= ml^2/12× angular accl..And kx=mg/2=>Angular accl.. =3g/lSo net accl is..L×angular accl. - accl of com Which is againg/2

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